Andi47
Overlord
Chances to solve an encounter in 3 turns with optimal strategy:
2 things to offer - 100%
3 things - 100%
4 things - 93.2%
5 things - 78.2%
6 things - 54.7%
7 things - 32.6%
8 things - 18.8%
9 things - 10.7%
Thanks!
Did anyone take notes, how many things can be selected to offer in each turn of difficulty levels 1, 2 and 3? (Based on these numbers, and assuming 7 things for each encounter ("typical negotiation in the middle of difficulty III" according to the announcement), the chance to solve every of the 16 encounters of difficulty 3 in 3 turns would be 0.326^16 = 1 in 61.4 million, which is in the same order of magnitude as the chance for winning the lottery*). I would be interested in the true number of things to offer in each encounter, so that I could calculate the true chance)
*) Chances for winning the lottery:
* Austrian "Lotto 6 aus 45": ~1 in 8 millions
* German "Lotto 6 aus 49": ~1 in 139.8 millions
* Swiss Lotto "6 aus 42 plus 1 aus 6": ~1 in 31 millions
* "Euromillionen": ~1 in 116.5 millions
Talking about "optimal strategy":
When there are 3 things to offer, I assume that I will succeed, when I do the following:
1st turn: offer thing #1 to everyone
2nd turn: offer thing #2 to everyone who is still there
3rd turn: offer thing #3 to the remaining people.
But what is the optimal strategy when there are more than 3 things to offer? Offer thing #1 to person #1, thing #2 to person #2, etc. in the first turn? If yes, how to proceed? (I would offer the things which turned "yellow" in a different order in the 2nd turn, and if there is space remaining, offer things #6 etc. if there are more than 5 things, to the other guys, but is this the optimal strategy?)